A simple PAM authentication module for authenticating Linux users against the AccountHub API.
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#!/usr/bin/env python
Copyright (C) 2013 Loris Tisisno <loris.tissino@gmail.com>
This program is free software: you can redistribute it and/or modify
it under the terms of the GNU General Public License as published by
the Free Software Foundation, either version 3 of the License, or
(at your option) any later version.
This program is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
GNU General Public License for more details.
You should have received a copy of the GNU General Public License
along with this program. If not, see <http://www.gnu.org/licenses/>.
import os
def custom_auth(user, password, command):
return os.system(command + ' ' + user + ' ' + password) == 0
def pam_sm_authenticate(pamh, flags, argv):
# the basic idea for getting the password via pam.conversation comes from
# http://benctechnicalblog.blogspot.it/2011/05/pam-python-module-for-out-of-band.html
user = pamh.get_user(None)
if user == None:
return pamh.PAM_AUTH_ERR
password = pamh.authtok
if password == None:
## got no password in authtok - trying through conversation...
passmsg = pamh.Message(pamh.PAM_PROMPT_ECHO_OFF, "Custom auth: ")
rsp = pamh.conversation(passmsg)
password = rsp.resp
# so we should at this point have the password either through the
# prompt or from previous module
if custom_auth(user, password, argv[1]):
return pamh.PAM_SUCCESS
return pamh.PAM_AUTH_ERR
except pamh.exception, e:
return e.pam_result
def pam_sm_setcred(pamh, flags, argv):
return pamh.PAM_SUCCESS
def pam_sm_acct_mgmt(pamh, flags, argv):
return pamh.PAM_SUCCESS
def pam_sm_open_session(pamh, flags, argv):
return pamh.PAM_SUCCESS
def pam_sm_close_session(pamh, flags, argv):
return pamh.PAM_SUCCESS
def pam_sm_chauthtok(pamh, flags, argv):
return pamh.PAM_SUCCESS